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faq:freedom-from-feedback [2015/04/21 16:26]
hess [Freedom from Feedback]
faq:freedom-from-feedback [2015/04/21 16:26]
hess
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 As a theoretical rule of thumb, a good decoupling requires a distance of 5 to 10 λ.(([λ] Lambda = Wave length = v/f with v∼3×10<​sup>​8</​sup>​ m/s.))\\ As a theoretical rule of thumb, a good decoupling requires a distance of 5 to 10 λ.(([λ] Lambda = Wave length = v/f with v∼3×10<​sup>​8</​sup>​ m/s.))\\
 However, in practive often a distance of 3 λ is sufficient. \\ However, in practive often a distance of 3 λ is sufficient. \\
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 At 2.1 GHz (e.g. UMTS) the formula returns 300'​000'​000/​2'​100'​000'​000 = 300/2100 = 0.14m. At 2.1 GHz (e.g. UMTS) the formula returns 300'​000'​000/​2'​100'​000'​000 = 300/2100 = 0.14m.